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- Newsgroups: alt.drugs.chemistry,alt.drugs,alt.psychoactives
- From: ez026264@dale.ucdavis.edu (Speed Raver)
- Subject: d-meth synthesis
- Message-ID: <Cu2397.F53@ucdavis.edu>
- Date: Fri, 5 Aug 1994 09:48:43 GMT
-
- Sorry if some of the spelling looks tweaky. My C key is acting really
- weird. Also, there are diagrams at the end for reference.
-
- SYNTHESES THAT SUCK:
-
- There've been a lot of synthesis methods proposed on UseNet for
- synthesizing methamphetamine. Thus far, I haven't seen one that I imagine
- would work.
-
- One, from Phrack magazine, is the "tried and true method" for prepping
- meth from Vick's nasal inhalers. Vick's nasal inhalers contain
- "l-desoxyephedrine," another name for "l-methamphetamine." The l- isomer
- of methamphetamine is the relatively inactive one, usable as a (mild)
- nasal decongestant. The d- isomer is the one that everyone wants and that
- Uncle Sam has declared is just too cool for anyone except doctors.
-
- The procedure described would extract the l-meth froom the inhalers and
- collect it and that's it. I'm sorry, but the Isomer Fairy can't wave
- her magick wand and reverse the chirality of the molecule. The only way
- to change between the two isomers is to oxidize the l-meth into
- phenylacetone, condense it with methylamine, then reduce it. Sorry, but
- soaking inhalers in HCl then separating the "juice" with Et2OH just won't
- do it. You'll get l-meth and that's that.
-
-
- A more credible souding one mentions that "methamphetamine is prepared by
- the calalytic reduction of pseudoephedrine in acetic acid" blahblahblah and
- then goes on to describe, not catalytic reduction via acetic acid, but
- reduction with sodium borohydride. I'm sorry to say that no method
- attempting to directly reduce (pseudo)ephedrine's hydroxyl group is going
- to work. You can't expose it to a strong acid, or a weak acid, or sodium
- borohydride, or even lithium aluminum hydride and expect it to reduce at
- all. As with the Vick's Inhalers "recipe," you get a lot of SOMETHING,
- but it ain't d-meth. All you'll be left with is your (pseudo)ephedrine
- and a bunch of acid, lithium, and/or sodium and lotsa hydrogen gas. This
- is because the hydroxyl group (the OH in ephedrine) is on a very acidic
- carbon (the first carbon away from the ring) and a hydroxyl group is very
- basic. If the hydroxyl were on the second carbon from the ring (the
- carbon with the amine group, the NH2 or NHCH3), there might be some
- chance, but it's not and there's not. You're not getting a basic group
- off an acidic carbon without a fight, and acids, borohydride, and
- LiAlhydride aren't gonna fight that hard.
-
-
- SYNTHESES THAT DON'T SUCK:
-
- One of the easiest ways to make methamphetamine is from amphetamine. Of
- course, this assumes you have amphetamine in the first place, but let's
- just pretend you have some and you want to spice it up a bit.
- The difference between amphetamine and methamphetamine is the addition of
- a single methyl group (CH3) to the amino group sticking off the middle
- carbon atom in the chain. Fortunately, substituting amines is really
- simple. Vaporize your amine (your amphetamine) with a bunch of vaporized
- chloromethane (CH3Cl, a solvent) and some gaseous pyridine...
- voila, the amino group takes the methyl from the chloromethane and lets a
- hydrogen go. The hydrogen joins the liberated chlorine, and the resulting
- HCl is soaked up by the pyridine. The pyridine is optional. Adding it
- drives the reaction a bit by pulling the excess HCl out of the equation,
- but it's not neessary.
-
-
- Assuming you don't have amphetamine lying around, an easy synthesis with
- a very high yield is to reduce the condensation product of phenylacetone
- and methylamine. The benefit of this method is that different amines can
- be used to produce novel N-alkyl amphetamines (ethamphetamine,
- tert-butylamphetamine, etc)
-
-
- Making it from ephedrine or pseudoephedrine is possible. The only
- difference between methamphetamine and (pseudo)ephedrine is that damn
- alpha-hydroxy group. Reacting your ephedrine with thionyl chloride
- replaes the OH with Cl to produce N-methyl-alpha-chloroamphetamine as an
- intermediate. Hydrogenating this product is easy: use lithium aluminum
- hydride, sodium borohydride, or even hydrogen gas with nickel or platinum
- metal as a catalyst. The product of this step is N-methylamphetamine and
- HCl. Evaporate off the water and you have methamphetamine hydrochloride.
-
-
- A surprisingly simple synthesis is possible from the amino acid
- phenylalanine, which is available at health food stores for about $14 for
- 100 tablets. Phenylalanine is 2-amino-3-phenylpropanoic acid, which is
- more or less amphetamine with a COOH where the CH3 should be at the end of
- the chain. Thionyl chloride will replace the OH with a Cl, which falls off
- and is replaced by H when you give it lithium aluminum hydride, sodium
- borohydride, or hydrogen gas and nickel/platinum. If you use hydrogen and
- metal for that step, you'll have to reduce the carbonyl group with one of
- the hydrides, so best save time + effort and use them and do both
- reductions at once. When that carbonyl is reduced, you now have
- amphetamine. Go back up to that first one I mentioned for upgrading
- amphetamine into methamphetamine.
-
-
- Note that azll of these (and probably anything anyone ever comes up with)
- will give you a mix of d- and l- isomers. The d- is cool, the l- is shit,
- remember. If you have time, energy, and equipment, you can separate the
- two and reprocess the l- into d- by oxidizing it and re-aminating it as
- described in the "critique" of the Phrack synthesis.
-
-
- DIAGRAMS:
-
- H
- /\\ / \ NH
- / \\ / \ /
- || | |
- || | |
- || | CH3 amphetamine
- \ //
- \//
- H
- /\\ / \ NCH3
- / \\ / \ /
- || | |
- || | |
- || | CH3 methamphetamine
- \ // has a CH3 at N that amphetamine doesn't
- \//
-
- OH
- | H
- /\\ / \ NCH3
- / \\ / \ /
- || | |
- || | | ephedrine and pseudoephedrine
- || | CH3 the difference is whether the OH
- \ // points up or down
- \//
-
- H
- /\\ / \ NH
- / \\ / \ /
- || | |
- || | |
- || | C=O phenylalanine
- \ // | compare to amphetamine
- \// OH
-
-
-
- Article 94300 of alt.drugs:
- Path: news.claremont.edu!paris.ics.uci.edu!csulb.edu!nic-nac.CSU.net!usc!howland.reston.ans.net!math.ohio-state.edu!cs.utexas.edu!chpc.utexas.edu!news.utdallas.edu!corpgate!bcarh8ac.bnr.ca!bcarh8ab.bnr.ca!bcarh697!yshan
- From: yshan@bcarh697.bnr.ca (Yogi Shan)
- Newsgroups: alt.drugs.chemistry,alt.drugs,alt.psychoactives
- Subject: Re: d-meth synthesis
- Date: 5 Aug 1994 21:43:01 GMT
- Organization: Bell-Northern Research, Ottawa, Canada
- Lines: 25
- Sender: yshan@bcarh697 (Yogi Shan)
- Distribution: world
- Message-ID: <31ubp5$rtq@bcarh8ab.bnr.ca>
- References: <Cu2397.F53@ucdavis.edu>
- NNTP-Posting-Host: bcarh697.bnr.ca
- Xref: news.claremont.edu alt.drugs.chemistry:53 alt.drugs:94300 alt.psychoactives:7585
-
- ez026264@dale.ucdavis.edu (Speed Raver) wrote:
-
- **> I'm sorry to say that no method attempting to
- **> directly reduce (pseudo)ephedrine's hydroxyl
- **> group is going to work.
-
- Your post was interesting, but this is not quite true.
- Direct hydrogenation over Pd or Pd on a carrier is well
- known and facile. You add a little perchloric,
- phosphoric or sulphuric acid, which esterifies the-OH
- group that you're complaining about.
-
- Thus making the intermediate halide via SOCl2, like
- you mentioned, is unecessary.
-
- **> Note that all of these (and probably anything
- **> anyone ever comes up with) will give you a mix
- **> of d- and l- isomers.
-
- Hydrogenation starting with (-) ephedrine, whether
- direct or via the halide, will give d-meth. If
- you start with dl-ephedrine, you get dl-meth.
-
-
- Yogi
-
-
-